Answer:
Option C
Explanation:
In equilibrium
Upward force= Downward force
$kx_{0}+F_{B}=mg$
Here , kx0 is . restoring force of spring and FB is buoyancy force
$kx_{0}+\sigma\frac{L}{2}Ag=Mg$
$x_{0}=\frac{Mg-\frac{\sigma LAg}{2}}{k}$
$=\frac{Mg}{k}(1-\frac{\sigma LA}{2M})$